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  5. 0100-0199/

0140 单词拆分 II

Solution

from typing import List

class Trie:
    def __init__(self):
        self.children = [None] * 26
        self.is_end = False

    def insert(self, word):
        node = self
        for c in word:
            idx = ord(c) - ord('a')
            if node.children[idx] is None:
                node.children[idx] = Trie()
            node = node.children[idx]
        node.is_end = True

    def search(self, word):
        node = self
        for c in word:
            idx = ord(c) - ord('a')
            if node.children[idx] is None:
                return False
            node = node.children[idx]
        return node.is_end


class Solution:
    def wordBreak(self, s: str, wordDict: List[str]) -> List[str]:
        def dfs(s):
            if not s:
                return [[]]
            res = []
            for i in range(1, len(s) + 1):
                if trie.search(s[:i]):
                    for v in dfs(s[i:]):
                        res.append([s[:i]] + v)
            return res

        trie = Trie()
        for w in wordDict:
            trie.insert(w)
        ans = dfs(s)
        return [' '.join(v) for v in ans]


if __name__ == "__main__":
    sol = Solution()
    print(sol.wordBreak("catsanddog", ["cat","cats","and","sand","dog"]))
    # ['cat sand dog', 'cats and dog']
    print(sol.wordBreak("pineapplepenapple", ["apple","pen","applepen","pine","pineapple"]))
    # ['pine apple pen apple', 'pine applepen apple', 'pineapple pen apple']
    print(sol.wordBreak("catsandog", ["cats","dog","sand","and","cat"]))
    # []