Solution
from typing import Optional
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def rob(self, root: Optional[TreeNode]) -> int:
def dfs(root: Optional[TreeNode]) -> tuple[int, int]:
if root is None:
return 0, 0
la, lb = dfs(root.left)
ra, rb = dfs(root.right)
# a: 选当前节点;b: 不选当前节点
return root.val + lb + rb, max(la, lb) + max(ra, rb)
return max(dfs(root))
if __name__ == "__main__":
sol = Solution()
# [3,2,3,null,3,null,1]
n1 = TreeNode(3)
n2 = TreeNode(2)
n3 = TreeNode(3)
n4 = TreeNode(3)
n5 = TreeNode(1)
n1.left, n1.right = n2, n3
n2.right = n4
n3.right = n5
print(sol.rob(n1)) # 7